Mathematically, this problem is called the weight problem of Mei, which is described as follows:

If there are n weights, the weights are M 1, M2, ..., Mn, and all weights from 1 to (M 1+M2+ ... +Mn) can be weighed, and one more weight is added, and the weight is Mn+1= (m

(all weights of M 1+M2+ ... +Mn+Mn+ 1).

If n = 1, M 1 = 1, the weights of all weights can be deduced as follows:

1,3,9,27,8 1,243,……

The weight should be 1, 3, 9, 27.

2=3- 1

4=3+ 1

5=9- 1-3

7=9+ 1-3

1 1=9+3- 1

14=27- 1-3-9. That is to say, on one side, put 27 grams of weights, and on the other side, put 1, 3 and 9 grams of three weights and the said articles.

40= 1+3+9+27.

You got it?