x? -x-2 & gt; 0
(x+ 1)(x-2)>0
X<- 1 or x>2
2x? +(5+2k)x+5k & lt; 0
(2x+5)(x+k)& lt; 0
[x-( -5/2)][x-(-k)]0
If the integer solution of the inequality group is only -2.
-5/2 & lt; -k & lt; three
Solution: -3
The value range of k is (-3,5/2).