As shown in the figure, in the trapezoidal ABCD, AD is parallel to BC, ∠ B = 90, BC = 6°, AD = 3°, DCB = 30, and points E and F start from point B at the same time and move to the right uniformly along the ray BC. It is known that the moving speed of point F is twice that of point E, and an equilateral triangle EFG is made above CB with EF as one side. The overlapping area of ABCD is y, and the functional relationship between y and x is obtained. ? Tip: There are three situations, one is when 0 < x ≤ 2, the other is when 2 < x ≤ 3, and the third is when 3 < x ≤ 6.