Analysis:

Open n power =e (ln (open n power)) power.

The original problem is transformed into: lim (e's (power of ln (power of a opening n)), (n tends to infinity, and a is a constant greater than 0).

And lim(ln(a opens to the power of n)), (n tends to infinity) is equivalent to lim( 1/n times ln a), and the limit of this formula is 0;

So the limit of the original problem is the 0 th power of e, which is 1.