The zeros of f'(x) are-1 and 2. The zero point of f(x) is not-1 and 2, and the specific value of the zero point of f(x) is not marked in the figure. Pay attention to whether there are apostrophes here.

Because f(x) is a cubic function, so. F'(x) is a quadratic function. The zero point of f'(x) is the extreme point of f(x)- minimum point-1 and maximum point 2. So f'(x) is symmetric about x = 1/2. So f'(0) = f'( 1), so the answer is 1.