(Because (x- 1)? ≥0)
Function y = (1/2) (x? -2x-3)
middle
Let t=x? -2x-3
rule
t≥-4,y=( 1/2)^t
And the function y = (1/2) t is a monotonically decreasing function.
So y = (1/2) t ≤ (1/2)-4.
= 16
y = ( 1/2) t > 0
So the range is (0, 16)