①∫∠C = 60，

∴PC=2CQ

∴8-2t=2t，

The solution is t=2,

When t=2, △PCQ is a right triangle;

② When 2PC=CQ,

From PC=2CQ: 2(8-2t)=t,

The solution is t= 165,

∴ When t= 165, △PCQ is a right triangle;

To sum up: when t=2 or 165, △PCQ is a right triangle;

(2) According to the meaning of the question, AP=2t, QB=8-t, △APM and △QNB are right triangles, and quadrilateral MNQP is right trapezoid.

In Rt△APM and Rt△QNB, pm = 3t, am = t, bn = 12 (8? t)，QN=32(8？ t)，

So MN=AB-AM-BN=4? 12t，S= 12(PM+QN)MN

S= 12[3t+32(8？ t)]×(4？ 12t)？ S=？ 38t2+8 has praise and tread. What is your evaluation of this answer? Put away comments//high quality or satisfaction or special types or recommended answers dottimewindow.iperformance & window.iperformance.mark ('c _ best',+newdate); Lawyer recommendation service: If your problem has not been solved, please describe your problem in detail and provide free professional consultation through Baidu Law Professional Edition. Other similar problems 20 16- 12-02 are known. As shown in the figure, △ABC is an equilateral triangle with a side length of 3cm, and the moving point P.Q starts from two points A and B at the same time and moves towards AB and BC respectively. Their serial numbers 1620 13-04-28 are known: as shown in the figure, △ABC is an equilateral triangle with a side length of 3cm, and the moving points P and Q start from two points A and B at the same time, and move uniformly in the directions of AB and BC respectively, 522017-12. Moving points P and Q start from point A and point B at the same time, and move uniformly in the directions of AB and BC, that is,152016-12-01. As shown in the figure, in equilateral △ABC, AB=9cm, and point P starts from point C, along CB side to point B at a speed of 2 cm/s, and point Q starts from point B, along BA side to point A, 442016-12-01. As shown in the figure, △AB, BC is an equilateral triangle with a side length of 4cm, and the moving point P.Q starts from two points A and B at the same time, along both sides of AB and BC, and is 1220 12- respectively. The moving point P starts from point A and moves along AB to the end point B at the speed of 1cm per second, while the other moving point Q starts from point B at142016-12-02. As shown in the figure, the side length of equilateral triangle ABC is 2. Point P and point Q start from point A and point C at the same time and move at the same speed, 221201-01-05. As shown in the figure, the side length of equilateral triangle ABC is 2. Point p and point q start from point a and point c at the same time, and move at the same speed. Point p along ray 32. More similar questions? & gt recommended for you: F.context('cmsRight', [{'URL':'/d01373f082025aaf511aa256e9edab64034f1a07? x-BCE-process = image % 2f resize % 2Cm _ lfit % 2Cw _ 450% 2Ch _ 600% 2c limit _ 1% 2f quality % 2Cq _ 85% 2f format % 2Cf _ auto '，' contractId':'A24KA00562 '，}，{ ' URL ':/s？ word = % E6 % AC % A7 % E6 % B4 % B2 % E6 % 9D % AF & sa = searchpromo _ ozb _ zhidao _ tuijian '，' src ':'/3 BF 33 a 87 e 950352 AAF 5 df 4954 143 fbf2b 2 1 18 b6b？ x-BCE-process = image % 2f resize % 2Cm _ lfit % 2Cw _ 450% 2Ch _ 600% 2c limit _ 1% 2f quality % 2Cq _ 85% 2f format % 2Cf _ auto '，' contractId ':' '，}])； Is Huaqiang North's second-hand mobile phone reliable? Why is the cost of cancer treatment getting higher and higher? What impact will the "network toilet" have? The price of electric cars has dropped many times. Is the quality guaranteed? I recommend f.context ('recbrand', [{"img": "\/86D6277F9E2F07083523F69DFB 24B 899A901F20d? x-BCE-process = image % 2f resize % 2Cm _ lfit % 2Cw _ 450% 2Ch _ 600% 2c limit _ 1% 2f quality % 2Cq _ 85% 2f format % 2Cf _ auto "，" url":"/hm.js？ 6859 ce 5a af 00 FB 00387 e 6434 E4 FCC 925 "； var s = document . getelementsbytagname(" script ")[0]； s.parentNode.insertBefore(hm，s)； })(); window . TT = 172006 1722；