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Known function fx ax2-ax-xlnx
g(x)=ax-a-lnx,g'(x)=a- 1/x,

( 1)x & lt; 1/a,g '(x)& lt; 0, g(x) is a decreasing function and f(x) is a decreasing function.

(2)x & gt; 1/a, g'(x) is increasing function, and f(x) is increasing function.

When x= 1/a, f( 1/a) takes the minimum value.

Given f (x) >: F( 1)=0 is the minimum value when x = 1, so a= 1.