If you want to calculate the air resistance, it is a very complicated model. First, assuming that air resistance can be ignored, then basketball is only affected by gravity in the air.

The initial speed of your basketball is V, and the angle between the horizontal lines is θ. According to the momentum theorem, mV=Ft(t is the time when your shooting power acts on basketball), then you can determine V, and the action time T of this shooting power is necessary, because the initial speed of basketball can not be determined only by power, and basketball is not acted by hands in the parabolic process.

Then there are several quantities you know. The height of the basket and the height of the hand when shooting are equivalent to two coordinates, which can be measured. Set the coordinates of the hand to (x0, y0) and the coordinates of the basket to (x 1, y 1).

Then find the third coordinate, that is, the highest point (x2, y2).

In the vertical direction, the basketball moves in a straight line with an acceleration g at a uniform speed, and the vertical component of the initial velocity is Vsinθ. When reaching the highest point, take T=Vsinθ/g, and when rising (Vsinθ)? /2g

During this time, the distance that the ball moves horizontally is VCOθ* T = V? sinθcosθ/g

Then you can find the coordinates (x2, y2) of the vertex.

Three coordinates, you can get a, b, c, b, c.

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Why did you have this strange feeling before? Because you don't take the position of the handle and the position of the basket into account, it is equivalent to shooting without knowing where the basket is and where you are standing. In this case, you can't score, hehe.

And you stand in different positions, and your basketball parabola is different. It is impossible to throw the ball in the same direction with the same force in different positions.