D(5x+ 1 1) can be understood as the differential of the independent variable (5x+ 1 1), and d(5x+ 1 1) = 5dx, so dx =1.
definition
Let the function f(x) be continuous on the interval [a, b], and divide the interval [a, b] into n subintervals [x0, x 1], (x 1, x2), (x2, x3), ..., (xn-/kloc-0). We can know that the length of each interval is △x 1=x 1-x0, and any point ξi( 1, 2, ..., n) is used as the summation formula (xi- 1, xi).
. This summation formula is called integral sum, and let λ = λ=max{△x 1, △x2, …, △xn} x2, …, △ xn} (that is, λ is the maximum interval length). If λ→0, the limit of integral sum exists, then this limit is called the definite integral of the function f(x) in the interval [a, b], and it is written as
And the function f(x) is integrable in the interval [a, b].
Where: a is called the lower integral limit, b is called the upper integral limit, the interval [a, b] is called the integral interval, the function f(x) is called the integrand variable, f(x)dx is called the integrand expression, and ∫ is called the integral symbol.
It is called definite integral because the value obtained after its integration is definite and constant, not a function.
According to the above definition, if the function f(x) can be integrated in the interval [a, b], there is a special division of n equal parts:
Especially, according to the above expression, when the [a, b] interval happens to be the [0, 1] interval, the integral expression of the [0, 1] interval is:
References:
Baidu encyclopedia entry definite integral