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Cheng Dawei, a mathematician in China in the Ming Dynasty, once asked an interesting question. There is a man.
Ancient mathematicians in China once put forward an interesting problem of hundred sheep. One man is driving a flock of sheep in front, and another man is leading a sheep in the back. The man behind asked the sheep driver, "Do you have 100 sheep?" The shepherd replied, "I have such a flock of sheep, half of which and a quarter of which." Bring me your sheep, too. I happen to have 65,438+000 sheep. " How many sheep are there in this group?

A drives the sheep to chase the grass, and B pulls a fat sheep behind; Do you want to ask A and 100? Jia Yun said that there is no difference. If you have to gather together in such a group and add a small group, you have to gather together one by one. Who can guess the mystery?

The meaning of the title is: A is driving a flock of sheep on the grass, and B is leading a fat sheep to follow A closely. B asked A, "Do you have a hundred sheep?" Answer: "If there is such a group, add a semigroup, add a quarter group and add one of yours, which is 100." Excuse me, how many sheep have been driven at a time?

This topic was published in the book Arithmetic Unity by Cheng Dawei, a famous mathematician in Ming Dynasty. According to Cheng Dawei's account, this question, as well as other calculations in the form of poetry, was written in his spare time when he participated in the compilation of Yongle Dadian at 1406. This problem is not only widely circulated in China, but also widely quoted or adapted by many mathematicians abroad. This problem is a fractional application problem, please try it.

Answer:

The solution of arithmetic method is: (100-1) ÷ (1+1+1/4) = 36.

Because we regard the original sheep as the unit "1", add another such unit "1", add one-half and one-quarter units "1", subtract 1 from the total (100), and then divide it to get 36 sheep.

The solution of the equation method is: Solution: Let A have x sheep. X+X+X/2+X/4+1=100 The final solution is: x=36.

The above results should be misunderstood: that is, "semigroup small semigroup" should be understood as "1/2 group multiplied by 1/4", that is, 1/8 group. If we set the flock of sheep as X, we get X+X/8+ 1= 100.

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