Solution: Let the velocity of water flow be v 1 and the velocity of Xiao Wang be v2.

Then the distance from Xiao Wang to the kettle after 10s =10 (v1+v2-v1) =10V2.

It took X seconds for Xiao Wang to catch up with the kettle at this distance.

XV 1+ 10 v2 = X(v 1+V2)。

10v2=xv2

x= 10