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Mathematics examination paper for the next semester of senior two.
Simulated test questions (answer time: 60 minutes)

A multiple-choice question (3 points × 10 = 30 points)

1. The result of calculation is ()

A.4 B. 2 C. D

2. If known, the median term in the ratio of A and B is ()

A. 5th century BC

3. If two of the equations hold, then ()

A. 2 BC to 3 BC.

4. if c is the golden section of line segment AB, AC > BC, if ab = 1, AC = ().

A.0.6 18 BC

5. The root of the equation is ()

A.B.

C.D.

6. The following proposition is true ()

A quadrilateral with equal diagonal lines is a parallelogram.

A quadrilateral with diagonal lines perpendicular to each other and divided into two is a diamond.

A quadrilateral with four equal sides is a square.

A quadrilateral with right angles is a rectangle.

7. Every outer angle of a polygon is 30, so the number of sides of the polygon is ().

A.b . 18 c . 10d . 12

8. The price of a commodity after two consecutive price reductions 10% is one yuan, and the original price of the commodity is ().

A.B.

C.D.

9. In △ABC, d is a point on the side of AC, ∠ DBC = ∠ A, and the length of CD is ().

A. 65438 BC+2 BC.

10. As shown in the figure, in trapezoidal ABCD, e and f are the midpoint of AB and CD respectively, and AD and BC are the two roots of the equation, then EF is ().

A. 1 B. 3 C. 2 D. 4

Two. Fill in the blanks (2 points × 9 = 18 points)

1. If it is a quadratic radical, the range of x is _ _ _ _ _ _ _ _.

2. The diagonal of a square has a diamond shape, but the diagonal does not have the property of _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _.

3. Please write a figure _ _ _ _ _ _ which is both central and axial symmetry.

4. Write a similar quadratic radical _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _.

5. If the equation has two equal real roots, the value of k is _ _ _ _ _ _ _ _.

6. Factorize the factors in the real number range: _ _ _ _ _ _ _ _

7. As shown in the figure, if ∠ Abd = ∠ C, write a similar triangle _ _ _ _ _ _ _ _ _ _ _.

8. If yes, then _ _ _ _ _ _ _

9. As shown in the figure, AB=CD, AD‖BC, AC⊥BD, AO = 1, CO = 2, then the height of trapezoidal AB = CD is _ _ _ _ _ _ _ _.

Three. Calculation (5 points +7 points = 12 points)

1.(5 points)

2.(7 points)

Know the value of.

4. Solve the equation (5 points +7 points = 12 points)

1.(5 points)

2.(7 points)

solve

5. Solving problems (6 points +7 points +7 points +8 points = 28 points)

1.(6 points) As shown in the figure, in right-angle ABCD, e is a point above BC, and DF⊥AE is in F, if AE = BC.

Verification: ce = Fe

2.(7 points) If the sum of the two roots of the equation about X is equal to the product of the two roots, solve the equation and find the value of m.

3.(7 points) Known: As shown in the figure, in trapezoidal ABCD, AD‖BC, E is the midpoint of AB, and CD = AD+BC.

Verification: DE⊥EC

4.(8 points) It is known that the quadrilateral ABCD is a right-angled trapezoid, AD‖BC, ∠ A = 90, point E is on AB, and ED⊥CD is on D. If, find the length of BC.

Test answer

1. Multiple choice questions.

1.B 2。 A 3。 C 4 explosive D 5。 A

6.B 7。 D 8。 D 9。 C 10。 C

2. Fill in the blanks.

1.2. The diagonals of the squares are equal.

3. rectangle 4. and

5.0 or 6.

7.△ Abd ∽△ACB

8.9.

Three. Calculate.

1. solution: original recipe

2. Solution:

4. Solve the equation.

1. solution:

2. Solution: Suppose, then the original equation is defined as

Finishing:

When was that

There is no solution to this equation.

When was that

Test: put each one in, and none of them is 0.

Is the solution of the original equation.

5. Answer the questions.

1.

Prove: ∵ quadrilateral ABCD is a rectangle.

∴BC=AD

Ae = BC, ∴ AE = AD

∴∠ 1=∠ADE

And ∠ ade+∠ 2 = 90, ∠ 1+∠ 3 = 90.

∴∠2=∠3

In Rt△DFE and Rt△DCE

∴Rt△DFE≌Rt△DCE

∴CE=FE

2. Solution: The equation can be simplified as follows

Let its two roots separate, and then

and

, namely

3. proof: find the midpoint f of CD, followed by EF.

rule

and

and

4. solution: if d is DF⊥BC in f, then DF‖AB.

∴∠ 1=∠3

∠ 3 +∠ 2 = 90.

∴∠ 1+∠2=90

∠∠2+∠c = 90。

∴∠ 1=∠C

∴Rt△AED∽Rt△FCD

That is all right

and

In Rt△DFC,

that is