1000×4x+ 1500( 108-5x)+2000 x≤ 147000
Solution: x≥ 10
Because x can only be a positive integer, the solution satisfying the condition is: x= 10.
Therefore, the mall has purchased at least 10 C TV sets.
(2) From the meaning of the problem:
4x≤ 108-x-4x ①
x≥ 10 ②
X from ① ≤ 12
The solution set of inequality group is 10≤x≤ 12.
∵x can only be a positive integer ∴ The solutions that meet the conditions are: x= 10, 1 1, 12.
Therefore * * * there are three procurement schemes:
Scheme 1: 40 units of Class A, 58 units of Class B and 0 units of Class C/KLOC-0. ..
Scheme 2: 44 sets of Class A, 53 sets of Class B, and Class C 1 1 set;
Scheme 3: 48 units of Class A, 48 units of Class B and 0/2 units of Class C/KLOC. ..