The Application of One-dimensional Linear Inequalities in Junior One Mathematics (Part Two) [Urgent]

Solution: (1) We buy X Class C TVs, 4 Class A TVs and (108-x-4x) Class B TVs. ..

1000×4x+ 1500( 108-5x)+2000 x≤ 147000

Solution: x≥ 10

Because x can only be a positive integer, the solution satisfying the condition is: x= 10.

Therefore, the mall has purchased at least 10 C TV sets.

(2) From the meaning of the problem:

4x≤ 108-x-4x ①

x≥ 10 ②

X from ① ≤ 12

The solution set of inequality group is 10≤x≤ 12.

∵x can only be a positive integer ∴ The solutions that meet the conditions are: x= 10, 1 1, 12.

Therefore * * * there are three procurement schemes:

Scheme 1: 40 units of Class A, 58 units of Class B and 0 units of Class C/KLOC-0. ..

Scheme 2: 44 sets of Class A, 53 sets of Class B, and Class C 1 1 set;

Scheme 3: 48 units of Class A, 48 units of Class B and 0/2 units of Class C/KLOC. ..