If the current speed is A, the still water speed of the ship is X, the countercurrent speed of the ship is x-a, and the speed of the kettle in the opposite direction is A, then the speed of the kettle leaving the ship is X-A+A = X.
The speed of the ship chasing the pot is x+a, and the pot is still drifting with A. If the speed of the ship and the pot are in the same direction, the speed of the ship chasing the pot is X+A-A = X.
So the kettle left for 10 minutes, and when it was found, it had already left the ship 10x.
If the distance between the boat and the kettle decreases by x per minute, then 10x/x= 10.
Or 10 minutes to catch up.
(Please accept if you are satisfied)