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20 1 1 Changping Mathematical Model Question 24 Question 2 Question 3 How to Prove Similarity Brief Process and Answer
Second question: ∠ AOB+∠ APB = 180.
△APB ∠ APB+∠ PAB+∠ PBA = 180。
∴∠PAB+∠PBA=∠APO+∠BPO
According to the first question, PA=PB.
∴∠PAB=∠PBA
OP is the bisector
∴∠APO=∠BPO
∴∠PBA=∠POB
The third question is vertical, and the last one is 4.