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This is the answer to the true question of 20 14 in mathematics for postgraduate entrance examination. I don't understand very well. I ask the great god for help.
The projection of curve L (corresponding surface) on the yoz plane is a straight line, so the integral corresponding to dydz is zero;

Therefore, dydz+dzdx= dzdx.

The projection of curve L (corresponding surface) on xoz plane is dxz = {(x, z) x 2+z 2 < = 1},

The projection of the curve L (corresponding surface) on the xoy plane is dxy = {(x, z) x 2+y 2 < = 1},

The integral corresponding to dzdx is equal to the integral corresponding to dxdy.