Playing with beans, one person takes an irregular quantity, and whoever gets it in the end loses. Is there any pattern?

Your question is, whoever succeeds will lose. Imagine that the first hand takes N- 1 at a time, and the second hand only takes the last one.

There is a similar problem in primary school mathematics, that is, 10 beans, and two people take turns to pick them up, each time 1 or two beans. Whoever picks it up last wins. This is a question of who will win if he is ahead. That is: first take the remainder of the total to 3, and then make up 3 according to the number taken by the other party.

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