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Mathematics page 46
(1) The general term formula of the first series is 4n-2, and that of the second series is 6n-4.

The word * * * can be understood as 4x-2=6y-4, that is, the point on the straight line y=(2x+ 1)/3, and the ordinate and abscissa of this point are positive integers. ..

Then the public * * * series is 2 14, 26, 38, 50, ...

That is, this series is 2+(n-1) x12 =12n-10.

(2) This problem can also be understood in this way. Two arithmetic progression have the same first term with tolerances of 4 and 6, so their common term tolerance is 12. The results will come straight out.