According to conventional thinking, there is no solution to this problem. However, if the problem requires two line segments, you can get the following results:

No matter how many portions are divided, the sum of each portion must be equal to the sum. Therefore, by calculating the sum of the figures in the chart, we can get:

8+6+3+ 18+5+3+2+7=52, which can be divided into 2×26, 4× 13 or 1×52.

It is impossible to divide it into 4× 13, because there is a 18 in the middle, which is already greater than 13, so we can only consider 2×26, so we can get two schemes: First, use two line segments (note: line segments! This is the requirement of the topic! ) add a border and make a rectangle to enclose 8 and 18, and 8+18 = 26; 6+3+5+3+2+7=26, the solution is over. The second answer: Also make a rectangle with two line segments and a border, and circle 5+3+ 18=26 in the lower left corner, and the rest is 8+6+3+2+7=26.

Of course, there can be a third solution: draw two line segments randomly in the box, and if they don't intersect with the border and numbers, they are equivalent to an area. Of course, the sum of the numbers in this area is itself, 52=52.