1(2) triangle BPD and triangle CQP have an angle B= angle c, which is the corresponding angle. If the moving speed of point Q is not equal to the moving speed of point P, BP is not equal to CQ. In order to make triangle BPD and triangle CQP congruent, BP=CP. At this time, BP=CP=8/2=4, CQ = BD = 5,5/(4/3) =15/4.

When the moving speed of point Q is15/4cm/s, triangle BPD and triangle CQP can be congruent.

2. Suppose that point P and point Q meet for the first time after x s, when point P moves 3X CM, point Q moves 15/4 X CM, and point Q catches up with p more than P (AB+AC). According to the meaning of the question,

15/4 X-3X= 10*2

Solution, X=80/3

At this time, q shift 15/4*80/3= 100CM, 100/28=3 and 16/28, 16.

After 80/3S, point P and point Q meet for the first time on the AB side of triangle ABC.