Analysis: As two cars, A and B, left Tianjin for Beijing at the same time, five hours later, A was 35 kilometers behind B.

Therefore, car B travels 35/5 kilometers more per hour than car A = 7 kilometers.

Therefore, the B car travels 34+7=4 1km per hour.

The second car travels more miles per hour than the first car: 35/5=7 (kilometers).

Train b runs every hour: 34+7=4 1 (km)

Answer: the speed of car B is 4 1km.