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Study and guide pioneer college entrance examination math problems
The largest integer divisible by 5 in 100 is 5*20= 100, the largest integer divisible by 3 is 3*33=99 and the largest integer divisible by (3*5= 15) is15 * 6.

So the sum of numbers divisible by 5 from 1 to 100 is: 5 * (1+2+…+20) = 5 * (1+20) * 20/2 =1050;

Sum of numbers divisible by 3: 3 * (1+…+33) * 33/2 =1683;

Sum of numbers divisible by 3 and 5 (that is, divisible by 15):15 * (1+…+6) * 6/2 = 315;

So the result is (1+2+…+100)-1050-1683+315 = 2632.