1. According to the requirements of the three equations in the topic, the values of the three equations △ = b 2-4ac are greater than 0, equal to 0 and less than 0 respectively.

The final inequality of formula 1 is: a 2+4 b- 12 > 0.

The final inequality of Formula 2 is: a 2- 12a+8+4b = 0.

The final inequality of the three formulas is: a 2-8a+4b-4 < 0.

Substitute two kinds into the right of one, three kinds and two kinds respectively ~ turn around and it's done.

a^2+4b- 12>a^2- 12a+8+4b a > 5/3

a^2-8a+4b-4 0，B+C-A > 0，B-C+A > 0，B-C-A < 0。

The result is delta < 0.

Equation has no solution ~

In fact, it seems that they are all △ = b 2-4ac ~ ~ Yes, it's still repetitive work ~ ~ I hope it will help ~ ~ Come on in math ~ Actually, I prefer geometry, which is more fun ~