2) If the vertical line from O to AC has a vertical foot of D, CE=√(OE2+OC2)=34/3, OD/OC=OE/CE.

OD =((5/3)√34)√34)/(34/3)= 5

3) If point Q is on BC and point P coincides with point E, OQ=OF=5.

If point Q is on AB, because the distance from O to AB = (7 √ 2)/2.

If point Q is on AC, because the distance from O to AC is 5, point Q is the vertical foot from O to AC, which coincides with D, and the bisector of ∠QOF also intersects AC at point P.

So, there are four possible situations. Please find the coordinates of point P by yourself (write the resolution function of the line where OP is located and sum the intersection of AC).