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The answer on page 120 of the math textbook for junior two students 1, 2,4 (1) 8.
P 120/ 1.s=90t(t≥0)

2. two, four

-5

decrease

4( 1)Y=4X

8. Let the resolution function be y=kx.

From the meaning of the question {2k=-3a.

ak=-6

∴a quadratic = 4;

So a = 2

Because the straight line passes through the fourth quadrant, the point (2, -3a) is in the fourth quadrant.

so-3a < 0; a>0

So a=2 gives k=-3.

So the resolution function is y=-3x.

I don't know if the textbook is different from yours! )