The intersection of y=-2x+3 and y axis is (0,3).
Parallel to the straight line y=5x, indicating equal slopes, and k=5.
The main resolution function is y=5x+b, which is substituted into (0,3).
y=5x-2
2. The linear function image passes through the intersection of the straight line y=2x-3 and the X axis, and also passes through the intersection of the straight line y=-3x-5 and the Y axis, thus obtaining the linear resolution function.
The intersection of y=2x-3 and X axis is (1.5,0).
The intersection of y=-3x-5 and y axis is (0, -5).
Let a resolution function be y = kx+b.
1.5k+b=0
b=-5
So k= 10/3.
The resolution function is y= 10/3x-5.
3. If the area of the triangle surrounded by the straight line passing through point P (-2,0) and X and Y axes is 3, find the functional relationship of this straight line.
The intersection of the function and the y axis is plus or minus 3*2/2=3.
Is (0, -3) or (0, 3)
Let a resolution function be y = kx+b.
B=3 or b=-3.
-2k+3=0-2k-3=0
k= 1.5？ k=- 1.5
The resolution function is y= 1.5x+3 or y=- 1.5x-3.
4. It is known that y-3 is proportional to x+2, and when x=- 1, y= three fifths.
(1) Find the relationship between y and x.
y-3=k(x+2)
When x=- 1, y=2.5 is replaced.
2.5-3=k(2- 1)
k=-0.5
So y-3=-0.5(x+2)
y=-0.5x+2？
y=-x+2
The intersection with the X axis is (2,0).
y=2x- 1
The intersection with the X axis is (0.5,0).
The base of the triangle is 2.5.
The intersection of two functions is (1, 1).
The height of the triangle is 1.
Area = 1*2.5*0.5= 1.25.