The train leaves every ten minutes, stops for one minute, comes again after ten minutes, and so on. ...
So it can be understood that the train stops every 1 1 minute 1 minute.
This person may arrive at any time in this 1 1 minute, and only qualified trains will stop in this 1 minute.
This minute accounts for 1/1of1minute, so the probability of encountering the event mentioned in the question is11/.
In addition: draw a long strip and divide it into four parts in this order: 10 cm, 1 cm, 10 cm, 1 cm. 1cm partial coloring. No matter how it is divided by 1 1cm, the colored part always accounts for11.
^_^