I solved it with the proportion of the third grade. . . I don't know if it's ok. . .

( 1)AP:AB=PM:BH

x:(2x+ 12)= 1.6:9.6

X=3 (m)

The distance between two street lamps is 12+2x= 18 (m).

(2) Suppose Wang Hua walks to the street lamp B, and his shadow length under the street lamp A is Y.

BC:AC=BD:AD

1.6:9.6=y:(y+ 18)

Y=3.6 meters

I'm not good at math either. . . See for yourself =? =