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Where is the missing cube area? Who can solve it with mathematics? Make it clear.
Hello, everyone. I saw a video on the Internet, and drew a triangle with paper, then divided it and reassembled it, resulting in the loss of triangle area. For verification, I got the same result after dividing it with paper, and the area was really less. I don't believe in evil, so I specially use solidworks to draw a triangle that simulates missing. The measurement and analysis results are as follows:

The dimension, width and vertical height of my original drawing are 5* 13mm. After splitting and recombination, it is 5.07* 13.2, and the longest hypotenuse is 14. 14. According to the approximate algorithm s = lw =14.14 * 0.07 = 0.9898, the extra area is approximately equal to1*1mm2;

In fact, this demonstration is caused by subtle mistakes and bad vision. The width of 0.07mm is about the size of hair, and the drawing is not fine enough to demonstrate on paper, so the slight difference is basically invisible.