1.X = 2.4 X = 9.7 X = 3.2 X = 5 X = 1.4 X = 2.9
2.( 1) Solution: Suppose his weight was X kilograms two months ago. X-3=93 X=96
(2) Solution: Let this street have X street lamps. 5X= 140 X=28
(3) Solution: Let the height of sika deer be x meters. 3.5X-X = 3.65 X = 1.46 1.46+3.65 = 5. 1 1
Textbook 75-76 pages
1 、( 1 )X ( 2 )X ( 3 )∨ ( 4)
2、X = 2.5 X = 10.5 X = 5.6 X = 3.6 X = 22 X = 65.6 X = 2 X = 8
3, the solution: let him play X every minute before exercise. X+55= 130 X=75
4. Solution: Let the width of this picture be x meters, then the length is 2X meters. 2 (2x+x) = 1.8x = 0.32x = 0.6m
The area is 0.18m2.
5. Solution: Let each table be 88.00+2X= 198.00 X=55.
6. Solution: Let Xiaohong walk x meters per minute on average. 7(45+X)=560 X=35
7. If □ in the original equation is regarded as X, then X+5= 13 X=8.
5 times =2.3 times =2.7 times
5X=7 X= 1.4
5÷X=5 X= 1
8. Solution: Let the boy on the right have x glass balls and the boy on the left have 2X. 2X-3=X+3 X=6 2X= 12
Reflections on the teaching of fraction 1
The preliminary understanding of fractions is a new course we learn after learni
First of all, we should think that the questioner should test your knowledge and then look for information from the ste