A complex set counts as C.
If the absolute value of S={x│x-2 is greater than 3}, then x >;; 5 or x
t = { x│a & lt; X & ltA+8}, then A.
Because S∪T=R, a+8 >: 5 and a <-1
All in all -3
S and t are United. If there is intersection, a+8 >; 5 or a
Only when a>- 1 and a+8.