Current location - Training Enrollment Network - Mathematics courses - Mathematical Proportion in the Sixth Grade of Primary School
Mathematical Proportion in the Sixth Grade of Primary School
Solution: 5: 3 = 5a: 3a3:1= 3b: b.

The perimeter of rectangle 1 is equal to the perimeter of rectangle 2, that is

(5a+3a)×2=(3b+b)×2 gives 2a = b.

The area of the rectangle 1 is 5a×3a= 15a? =50, so 3a? = 10

:3b×b=3b?

Because b=2a, 3b? =3×4a? =4×3a? =4× 10=40

That is, the area of rectangle No.2 is 40 square centimeters.