Math problem in the fifth grade of primary school: Party A and Party B have a total of 3,000 yuan, and Party A gives Party B 350 yuan. At this time, Party A is three-sevenths of Party B. How much does

Math problem in the fifth grade of primary school: Party A and Party B have a total of 3,000 yuan, and Party A gives Party B 350 yuan. At this time, Party A is three-sevenths of Party B. How much does Party A and Party B have? Solution: After A gives B, B's money is regarded as the unit 1.

Then B now has 3000/(1+3/7) = 2100 yuan.

It turns out that B is rich =2 100-350= 1750 yuan.

A Originally rich =3000- 1750= 1250 yuan.

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