How's the preparation for the next math exam in grade eight? When reviewing, you should do some simulation papers accordingly, and the effect will be better. I sorted out the test papers and answers of the second volume of eighth grade mathematics for everyone. Welcome to read!

Title of Mathematics Test Paper in Volume II of Grade 8 (full mark of this exam: 100, time: 90 minutes)

First, multiple-choice questions (3 points for each small question, ***24 points)

1. In the figure below, the figure with both axial symmetry and central symmetry is ().

2. As shown in the figure, in □, the vertical line of, intersects with this point, and the perimeter of △ is ().

A.6 B.8 C.9 D. 10

3. As shown in the figure, in the rectangle, they are the midpoints of the sides respectively. If,

, the area of the shaded part in the figure is ()

A.3 B.4 C.6 D.8

4. As shown in the figure, the diamond and delta overlap, at the top. If,,, then ().

a . 8 b . 9 c . 1 1d . 12

5.(20 15? Jiangsu Lianyungang senior high school entrance examination) known quadrilateral ABCD, the following statement is correct ()

A. when AD=BC, ABCD, the quadrilateral ABCD is a parallelogram.

B. when AD=BC and AB=DC, the quadrilateral ABCD is a parallelogram.

C. when AC=BD and AC bisects BD, the quadrilateral ABCD is a rectangle.

D. when AC=BD, AC? BD, quadrilateral ABCD is a square.

6.(20 15? Xiaogan, Hubei) It is known that each outer angle of a regular polygon is equal to 60? , then this regular polygon is ()

A. regular pentagon, regular hexagon, regular heptagon and regular octagon

7. If the diagonal length of a square is 2 cm, then the area of the square is ().

A.4 B.2 C. D

8.(20 15? As shown in the figure, point O is the center of the rectangle ABCD, and e is the point on AB. After folding, point B coincides with point O. If BC=3, the length of crease CE is ().

A.2 B

C.D.6

Fill in the blanks (3 points for each small question, 24 points for * * *)

9. As shown in the figure, in □ABCD, is it known? ,,, So,

______ .

10. As shown in the figure, at □, the midpoints of the sides are respectively, so * * * in the figure has a parallelogram.

1 1.(20 15? Hubei Xiangyang senior high school entrance examination) in? In ABCD, AD=BD, BE is the height next to AD,? EBD=20？ , then

The degree of A is _ _ _ _ _ _ _.

12. As shown in the figure, in △, the points are the midpoint of,, respectively.

The degree of C is _ _ _ _ _.

13.(20 15? It is known that e is a point on the diagonal AC of square ABCD, AE=AD, the intersection e is the vertical line of AC, and the intersection CD is at point F, then? Fashion = _ _ _ _ _ _.

14. If the sum of the internal angles of a convex polygon is 0, the number of diagonals drawn from a vertex is _ _ _ _ _ _ _.

15. As shown in the figure, in the rectangular ABCD, the diagonal sum intersects at point O, the length of BD is _____cm, and the length of BC is _____cm.

16. As shown in the figure, in the diamond, the diagonal line intersects with the point, and the point is the midpoint, which is known.

, then _ _ _.

Iii. Answering questions (***52 points)

17.(6 points) It is known that the circumference of □ is 40 cm, and the length of □is.

18.(6 points) Known, in □,? Divide the bisector into two sections and find the circumference of □.

19.(6 points) As shown in the figure, quadrilateral is the length of parallelogram,, and.

20.(6 points) As shown in the figure, in a rectangle, it intersects at one point and is equally divided at one point. If, what? Degree.

2 1.(6 points) As shown in the figure, a point is any point on the middle side of a square, which intersects with it. With this point as the center, rotate △ clockwise to get △. Try to explain: split equally? .

22.(6 points) As shown in the figure, in Rt△,? C=90？ ,? B=60？ E and f are the midpoints of AC and AB sides, respectively.

(1) Q? Degree of a;

(2) seek length.

23.(8 points) As shown in the figure, the quadrilateral is a diamond, and the perpendicular drawn from the midpoint intersects with the point.

The intersecting extension lines are at points.

(1) Verification:.

(2) If, find the perimeter of the diamond.

24.(8 points) As shown in the figure, m is the midpoint of the side BC of △ABC, and an is equally divided? BAC，BN？ AN is at point N, and the intersection of BN and AC extends to point D. It is known that AB= 10, BC= 15, and MN=3.

(1) verification: BN = DN

(2) Find the perimeter of △ABC.

Reference answer 1 analysis. The eighth grade mathematics examination paper Volume II C: Options A and B are centrosymmetric figures but not axisymmetrical figures, Option C is centrosymmetric and axisymmetrical figures, and Option D is axisymmetrical but not centrosymmetric figures.

2.b analysis: in the parallelogram,

Because the vertical lines intersect, so.

So the circumference of Delta is

3.b analysis: because the area of rectangular ABCD is,

So the area of the shaded part is 0, so choose B.

4.d analysis: connection, set at the intersection.

Because the quadrilateral is a diamond,

So there's ...

In the delta, because,

So ...

In the delta, because,

So ...

So ...

So choose D.

5.b analysis: one set of quadrangles with parallel opposite sides and another set of quadrangles with equal opposite sides may be isosceles trapezoid, so item a is wrong; Two groups of quadrangles with equal opposite sides must be parallelograms, so item B is correct; A quadrilateral with equal diagonals and one diagonal bisecting the other diagonal is not necessarily a rectangle, so item C is wrong; Quadrilaterals with equal diagonal lines and perpendicular to each other are not necessarily squares, so item D is wrong.

6.b analysis: Let the regular polygon be an N-polygon, because the sum of the outer angles of the regular polygon is 360? , so n=

7.b analysis: as shown in the figure, in the square,

Then,

So, that is to say,

So the area of the square is 2, so choose B.

8.a analysis: according to the nature of graphic folding, we can get:? BCE=？ ACE=？ ACB，

B=？ COE=90？ BC=CO= AC, so? BAC=30？ ,

So what? BCE=？ ACE=？ ACB=30？ Because BC=3, CE=2.

9. 12 analysis: Because quadrangles are parallelograms,

So ...

Because again? So, so.

10.4 analysis: Because in □ABCD, e and f are the midpoint of AB side and DC side respectively.

ABCD, so the quadrilateral AEFD, CFEB and DFBE are all parallelograms, plus □ABCD itself, * * * has four parallelograms, so the answer is 4.

1 1.55? Or 35? Analysis: When the vertical foot of high BE is on AD, as shown in figure (1),

Answer to the question 1 1 (1)

ADB=90？ -20? =70? . Obtained by AD=BD? A=？ DBA= =55？ .

When the foot E is on the extension line of AD, as shown in Figure (2),

Answer to question 1 1 (2)

BDE=90？ -20? =70? And then what? ADB= 1 10？ ,

By AD=BD？ A=？ ABD= =35？ .

So ...

12. analysis: from the meaning of the question to the conclusion,

Points d and e are the midpoint of AB and AC respectively. DE is the center line of △ABC,

∥ ,? .

13.22.5? Analysis: from the quadrilateral ABCD is a square, can you know? Bad =? D=90？ ,

CAD=？ Bad =45? .

By FE? Do you know AC? AEF=90？ .

In Rt△AEF and Rt△ADF, AE=AD, AF=AF,

Rt△AEF≌Rt△ADF(HL)，

FAD=？ FAE=？ CAD=？ 45? =22.5? .

14.6 analysis: according to the meaning of the question, it is found that this polygon is nonagon, so the number of diagonals drawn from a vertex of nonagon is

15.4 analysis: because of cm, it is cm. Because again, so cm.

, so cm

16. Analysis: ∵ The quadrilateral is a diamond. , .

Again? , .

In Rt△, from Pythagorean theorem, we get.

Point is the midpoint? Is the center line of delta? .

17. Solution: Because quadrangles are parallelograms,

Let centimeters, centimeters,

Because the perimeter of the parallelogram is 40 cm,

So, the solution is,

So ...

18. Solution: Set? The bisector of intersects the point, as shown in the figure.

Because so.

Again, so,

So ...

.

(1) When,

The circumference of □ is;

2 when,

The circumference of □ is.

So the circumference of □ is or.

19. Solution: Because the quadrilateral ABCD is a parallelogram,

So ...

Because, therefore,

So ...

Therefore, the lengths of are respectively

20. solution: because it is equally divided, so.

I know, so

Delta is an equilateral triangle, so

Because,

So delta is an isosceles right triangle, so.

So,,, at this time.

2 1. Solution: Because △ rotates clockwise, △ is obtained.

So delta delta, so.

Because so

Because of this. ...

So ...

So, split it equally? .

22. solution: (1)∵ in Rt△ABC,? C=90？ ,? B=60？ ,

A=90 B=30？ , that is? The degree of a is 30? .

(2) By (1),? A=30？ .

In Rt△ABC,? C=90？ ,? A=30？ , AB=8 cm,

.

E and f are the midpoint of sides AC and AB, respectively,

EF is the center line of △ABC,

23.( 1) Proof: Because the quadrilateral is a diamond, so.

Because this is the middle vertical line, so.

Because, therefore. (2) Solution: Because ∨, so.

Because of this.

Because, therefore,

So delta is an isosceles triangle,

So ... So ...

So the circumference of a diamond is.

24.( 1) Proof: In △ABN and △ADN,

∵ ? 1=? 2，AN=AN，？ ANB=？ Besides,

△ABN?△ADN，？ BN= DN。

(2) Solution: ∫△ABN?△ADN,? AD=AB= 10，DN=NB。

Point m is the midpoint of BC. MN is the center line of δ δ△BDC,

CD=2MN=6, so the circumference of △ ABC = AB+BC+CD+AD =10+15+6+10 = 4 1.

The new lesson of the final review plan for the second volume of eighth grade mathematics has been finished, and the intense review has begun. How to review efficiently is the key to ensure students to achieve ideal results in the exam. Now make the following review plan:

First, review is divided into three rounds.

1, Unit 6 of this book * * *, with the help of the review number, do a round of review once a week, and build your own knowledge system while reviewing basic knowledge and skills.

2. Special review. The test sites of this book are roughly divided into: the proof of geometric triangle, the translation and rotation of graphics, the proof of parallel edges, the algebraic part of unary linear inequalities and unary linear inequalities, factorization, fractions and fractional equations. Through special intensive training, students can further explore the relationship between knowledge, clarify the internal relations, and cultivate the ability to analyze and solve problems.

3. Comprehensive and intensive exercises of examination papers, using comprehensive questions to examine students, improve students' ability to solve practical problems by using what they have learned, and check and fill in the blanks of relevant knowledge at the same time, thus improving teaching quality.

Second, the specific measures

1, learn from Gao's practice and regroup the students in Class A according to their math scores. There are four floors, A 1, A2, B 1 and B2, and each floor has 16 students. Let the students in the same group compete with each other, formulate different customs clearance standards, and focus on implementation, but stay after school at noon. The students in Class B focus on praising the students who have passed the exam, mobilizing their enthusiasm and moving every student.

2. Carefully design questions and exercises to solve the problems in students' study, and put the same types of questions together to form a problem-solving method to improve classroom efficiency.

3. Test the learning effect in the classroom in time, find out the teaching loopholes, and ensure that the basic knowledge is firmly mastered, and the same type of questions will not lose points again.

4. Stabilize students' mood, talk to students alone appropriately, encourage students to step up review, and set different learning goals for students at different levels so that children can? Jump down and pick peaches? Do well in the final.

Third, the ultimate goal.

Through the final review, let children learn mathematics for one semester, strive for their best results, and establish confidence in mathematics. Class 8 (1) and Class 8 (2) can be among the best in mathematics, rising steadily, improving the passing rate, reducing the low score rate, shortening the gap with other classes, and doing their best to make great progress in the comprehensive ranking of Class 8 (1) and Class 8 (2).

Everyone should take seriously the math test papers and answers in the second volume of the eighth grade. After reading the above materials for everyone, are you still unfinished? I further recommended other video learning courses for everyone in Grade Two, and every subject was broken one by one! (Click on the picture to enter experiential learning directly! ! ! )

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