There are 2000 grams of water in two containers. Take it out of container a.

1/3 water, take out 1/4 water from container b,

Results1400g of water remained in the two containers. How much water is there in each container?

Let A have x grams, then B has (2000-X) grams.

1/3X+ 1/4(2000-X)= 2000- 1400

1/3X+500- 1/4X=600

1/ 12X= 100

X= 1200

B original

2000- 1200=800 (g)

2. Aggregates A and B are * * * 1764kg, of which 25% are used for aggregate A and 504kg for aggregate B.. At this time, the remaining amount of the two piles of sand and stones is the same. How many kilograms were there in the original two piles of sand and gravel?

Let A have x kilograms, then B has (1764-X) kilograms.

( 1-25%)X= 1764-X-504

0.75X+X= 1260

1.75X= 1260

X=720

B original

1764-720= 1044 (kg)

3. Party A and Party B bought a fruit together. Party A bought 2/5, 5.5 kilograms more, and Party B just bought half. How much does this box of fruit weigh?

Suppose this fruit weighs x kilograms.

2/5X+5.5= 1/2X

1/ 10X=5.5

X=55

Or: B just bought half, which means A also bought half. 5.5 kg is the difference between 2/5 and 1/2. 5.5 Divide directly by the difference between 2/5 and 1/2, which is the weight of the whole box of fruit.

5.5÷( 1/2-2/5)

=5.5÷ 1/ 10

=55 kg

4. A motorcade delivered a batch of goods, which was 85 tons on the first day, and the remaining 8/ 15 was short of 3 tons the next day, and the rest was finished on the third day. It is known that the third day is less than the second day 15 tons. How many tons are there in this shipment?

Solution: According to the fact that the third day is less than the second day's 15 tons, it is inferred that the second day is 8/ 15, so the third day is 7/ 15+3 = 265438.

The number of shipments on the second and third days.

21115 = 315t

Gross tonnage 3 15+85=400 tons.