Odd function images are symmetric about the origin.

X 1, x2 >；; 0 has [f (x1)-f (x2)]/(x1-x2) > 0, available:

F(x) is increasing function on (0, positive infinity), so f(x) is also increasing function on (-infinity, 0).

f(2)=0，f(-2)=0

On (0, positive infinity) 0 < x & lt2f (x) < =0; x & gt=2，f(x)>0

On (-infinity，0)x < =-2 f(x)& lt； =0; -2 & lt； x & lt0，f(x)>0

Odd function x=0 f(0)=0

The solution set of inequality xf(x)< 0 is _ (-2,0) ∩ (0,2).