= 1+( 1-2 inches x/2)

=-2 inches x/2+2

therefore

f (cos x/2)=-2cos x/2+2，2，f(sin x/2)

= 1+cosx

=(cos x/2)^2+(sin x/2)^2+(cos x/2)^2-(sin x/2)^2

=2*(cos x/2)^2

= 2 *( 1-(x/2)^2)

Substitute so that t=sin x/2.

Then f (t) = 2 * (1-t 2)

Let t=cos x/2.

Then f(cos x/2)

=2*( 1- (cosine x/2) 2)

=2* (symplectic x/2) 2

= 1-cos x, 1, a complex function problem in higher mathematics; F (sin x/2)= 1+cosx, then f (cos x/2)=?

F (sin x/2)= 1+cosx, then f (cos x/2)=?