Odd function f(x) monotonically increases in (0,+infinity), and f( 1)=0, so it monotonically increases in (-infinity, 0), and f(0)=0.

When x> 1, f (x) > f (1) > 0so (x-1) f (x) > 0.

When x = 1 and f (x) = 0, then (x- 1)f(x)=0 is not satisfied.

When 0

When x = 0 and f (x) = 0, it is not satisfied.

When-1 =

When x