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Solutions to the problem of shaking hands in junior high school mathematics.
n=2 s= 1,n=3 s=3= 1+2,n=4 s=6= 1+2+3,n=5 s= 10= 1+2+3+4,n=6 s= 15= 1+2=3+4+5

To sum up, when n people shake hands (n≥2), the number of handshakes is s =1+2+3+...+(n-1).

Use arithmetic progression formula, that is, s=n(n- 1)/2.

When n=52, s = 52 (52-1)/2 =1326.

Is it detailed Comment