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Answers to the last question of Nantong Mathematics Entrance Examination in 2008.
28. Solution: (1) ∫ d (-8,0), the abscissa of ∴B is-8, so it is substituted.

,y =-2。

The coordinate of point B is (-8, -2). And point A and point B are symmetrical about the origin ∴a(8 2).

therefore

......................................................, 3 points.

(2)∵N(0, -n), b is the midpoint of CD, and the four points A, B, M and E are all on hyperbola.

,B(-2m,-

),C(-2m,-n),E(-m,-n)。

.........................., 4 points.

S

Rectangular DCNO

,S

△DBO

=

,S

△OEN

=

Seven points ... Seven points.

∴S

Quadrilateral OBCE

=

S

Rectangular DCNO

Constitute noun plural

△DBO

-

S

△OEN

=k.∴

.

................................., eight.

In a straight line

And hyperbola

, get a (4, 1), b (-4, 1),

∴ c (-4,-2),M(2,2) .............................................................................................................................................

Let the analytical formula of straight line CM be

From c and m on this straight line, you can get

solve

.

The analytical formula of ∴ linear centimeter is

.......................... 1 1 min.

(3) As shown in the figure, AA is respectively.

1

⊥x axis, mm

1

⊥x axis and vertical foot are one respectively.

1

、M

1

.

(Question 28)

y

O

A

x

B

M

Q

A

1

P

M

1

Let the abscissa of point A be A and the abscissa of point B be -A, then

.

In the same way; In a similar way

, ....................... 13.

...................... 14.