Let OB=a, S△OAB=34a2=3, (2 points).

∴·∴ob=2(2，0)。 (3 points)

(2) Branch A (1, 3), (4 points)

Substitute a (1, 3) and b (2 2,0) into y=kx+b to get k+b = 32k+b = 0, (5 points).

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