2x+π/3=0 → x=-π/6，y=0？ That is, the point (-π/6,0)

2x+π/3=π/2 → x=π/ 12，y=2？ That is, the point (π/12,2)

2x+π/3 = π→ x = π/3, and y = 0 is the point (π/3,0).

2x+π/3=3π/2？ → x=7π/ 12, y=-2 is the point (7π/ 12, -2).

2x+π/3 = 2π→ x = 5π/6, and y = 0 is the point (5π/6,0).

As shown in the figure: