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Seventh grade, the first volume of mathematical innovation training, 14 class, 7 questions (1). (2) the answer?
Solution: (1) ∵ AB

(1) when a is positive and b is negative.

The original formula =-a/a+b/b+(-ab/ab) =-1+1+(-1) =-1.

② When A is negative, B is positive.

The original formula = a/a+(b/-b)+(-ab/ab) =1+(-1)+(-1) =-1.

From ① ②: the value is-1.

(2)m+n=0,ab= 1

Original formula =m+n/a+b- 1/ab.

=0÷ 1- 1÷ 1

=0- 1

=- 1