First, the primary school part 1, each copy × number of copies = total; Total number of copies/number of copies = number of copies; Total number of copies = 2, / Cube: V: Volume A: Surface area of side length = side length × side length× ×6 S Table =a×a×6 volume = side length× side length V = A×A×A×A 3, rectangular C perimeter S area A side length perimeter = (length+width )× 2 c = 2 (a+b) area = length× Triangle s area a bottom h height area = bottom x height ÷2 s=ah÷2 triangle height = area x trapezoid: s area a top bottom b bottom h height area = (top bottom+bottom) ÷ high cylinder: v volume h: height s bottom area r bottom radius c bottom perimeter (1) lateral area = bottom perimeter. Kloc-0/0, Cone: V volume H height S bottom area R bottom radius volume = bottom area× height÷ 3 total number ÷ total number = sum difference problem formula (sum+difference) ÷ 2 = large number (sum-difference) ÷ 2 = decimal sum and multiple problem sum ÷ (multiple-/kl) Tree planting on the non-closed line can be divided into the following three situations: (1) If trees are planted at both ends of the non-closed line, then: number of plants = number of segments+1 = total length ÷ plant spacing-1 total length = plant spacing × (number of plants-1) plant spacing = Then: number of plants = number of nodes = total length ÷ plant spacing = plant spacing × number of plants = total length ÷ number of plants (3) If trees are not planted at both ends of the non-closed line, Then: number of plants = number of nodes-1 = total length ÷ plant spacing-1 total length = plant spacing × (number of plants+1) plant spacing = total length ÷ (number of plants +65438) The quantitative relationship of closed-line tree planting problem is as follows = ÷ two. Meeting distance = speed × meeting time = meeting distance; The sum of speed and speed = meeting distance; Meeting time; Catch up with the problem; Distance = catch up with time; Distance; Speed difference = catching distance; Catch up with time; Downstream velocity = velocity-velocity = (downstream velocity+countercurrent velocity) ÷2 Velocity = (downstream velocity-countercurrent velocity) ÷2 Concentration problem Solute weight+solvent weight = solution weight100% = concentrated solution weight × concentration = solute weight/concentration = solution. × 100% increase or decrease = principal× increase or decrease percentage discount = actual selling price ÷ original selling price× 1 00% (discount <1) interest = principal× interest rate× time after tax interest = principal× interest rate× time × (1-) M = 10 decimeter 1 decimeter = 1 0cm 1 cm/cm1hectare = 1000 m21m2/kloc- Kloc-0/000g 1 kg = 1 kg RMB unit conversion 1 yuan = 10 angle/angle = 10 minute1yuan = 65438. In 2000, 1 year =1February (3 1 day) was:1\ 3 \ 5 \ 7 \ 8 \10 \/February (30. Leap year 366 days 1 day =24 hours 1 hour =60 minutes 1 minute =60 seconds 1 hour =3600 seconds. The formula for calculating the perimeter, area and volume of primary school mathematics and geometry is 1, and the perimeter of rectangle = (length Area of rectangle = length× width S=ab 4, area of square = side length× side length S=a.a= a 5, area of triangle = bottom× height ÷2 S=ah÷2 6, area of parallelogram = bottom× height S=ah 7, area of trapezoid = (upper bottom+lower bottom) ×