I will tell you the answer to the following question, but I don't know how it came about. Please write out the calculation process, thank you!
f(x)=x^2-3x/2-m
=(x-3/4)^2-9/ 16-m
Because [- 1, 1] has real roots.
So f (-1) >: = 0;
f( 1)>=0;
-9/ 16-m & lt； =0
Just solve three equations.