On behalf of Jimmy Dovich, the formula of problem 2482 in mathematical analysis exercise set.

v =(2π/3)∫& lt； α，β& gt； r^3(θ)sinθdθ

V = (2π/3) ∫is obtained.

=-(2π/3)∫& lt； 0，π/2 & gt； 64( 1+cosθ)^3d( 1+cosθ)

= -(32π/3)[( 1+cosθ)^4]<； 0，π/2 & gt； = 160π