This problem can be seen from the last two sessions. It is observed that only the last term of this polynomial contains the 10 square term of x, so 10 of x.

The coefficient of the square term should be equal to 1 at the left end of the equation, and the coefficient of the square term should be A [1] 10 according to the expansion of the right end a[ 10].

So a [10] =1;

With the above analysis, because a[9] is needed, the ninth power of the left x has not been proved to be 0, and only the last two terms on the right contain the ninth power of x, so the expansion coefficients of the right a[9] (x+ 1) 9 are a[9] and a [10] (x+/kloc-0.

10a[ 10], so there is.

A[9]+10a[ 10]=0, so a[9]=- 10.

Note [] stands for subscript and [] stands for power.