Topic: A, B and C play chess. After each game, if it is a draw, the two will continue to play until the outcome is decided. The loser will step down and the other person will play against the winner. After several games, A won four games, lost two games, and B won three games and lost three games. If C lost three games, how many games did C win?

We regard victory as+and failure as-. No matter how many games you play, there is always a winner and a loser, which means that all positive sums are equal to all negative sums.

A wins 4 and loses 2, marked as +4 and -2.

B wins, 3 loses, and 3 is +3, -3.

C MINUS 3, recorded as: -3.

The sum of all negative numbers is: -3-3-2=-8

That is, * * * lost eight innings, so the victory should also be eight innings, so the victory of C is:

8-(+4+3)= 1 field.