Multiply the second term by 2 and then add the square of the third term to equal the fourth term. 3×2+ 13× 13= 175
Multiply the third term by 2 and then add the square of the fourth term to equal the fifth term. 13× 2+175×175 = 30651,choose B.
2. Add every other number
4+ 1 1= 15
8+ 12=20
1 1+ 14=25
12+? =30
? = 18
3.8=[0+ 1+3]*2-0
22=[0+ 1+3+8]*2-2
64=[0+ 1+3+8+22]*2-4
190=[0+ 1+3+8+22+64]*2-6
4. Divide the original number into two numbers, such as 12 into 1 and 2, and 28 into 2 and 8.
Then 2/ 1=2
8/2=4
18/3=6
32/4=8
According to this rule, the combination option should be 10/ 1= 10, so choose 1 10.
5.( 1-3) ×(2-3) = 3
(5-3)*(6-3)=6
(6-3)*(6-3)=9
(6-3)*(9-3)= 18
(9-3)*( 18-3)=90 Choose C.
6.22+36- 1=57
36+(- 12)-2=22
- 12+5 1-3=36
5 1+? -4=- 12? =-59 choose D.
7. The rule is that the sum of the first item plus the hundredth, tenth and third digits of the first item is the second item. For example:
256+(2+5+6)=269
269+(2+6+9)=286
......
So the number in brackets is 302+(3+0+2)=307. Choose B.
These topics are quite difficult, but after careful observation and several attempts, you can still find the rules. I wish you success in your exam!