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Please help us solve several math problems in the civil service exam: please explain why!
1. The first term is multiplied by 2, and then the square of the second term is equal to the third term. 2×2+3×3= 13

Multiply the second term by 2 and then add the square of the third term to equal the fourth term. 3×2+ 13× 13= 175

Multiply the third term by 2 and then add the square of the fourth term to equal the fifth term. 13× 2+175×175 = 30651,choose B.

2. Add every other number

4+ 1 1= 15

8+ 12=20

1 1+ 14=25

12+? =30

? = 18

3.8=[0+ 1+3]*2-0

22=[0+ 1+3+8]*2-2

64=[0+ 1+3+8+22]*2-4

190=[0+ 1+3+8+22+64]*2-6

4. Divide the original number into two numbers, such as 12 into 1 and 2, and 28 into 2 and 8.

Then 2/ 1=2

8/2=4

18/3=6

32/4=8

According to this rule, the combination option should be 10/ 1= 10, so choose 1 10.

5.( 1-3) ×(2-3) = 3

(5-3)*(6-3)=6

(6-3)*(6-3)=9

(6-3)*(9-3)= 18

(9-3)*( 18-3)=90 Choose C.

6.22+36- 1=57

36+(- 12)-2=22

- 12+5 1-3=36

5 1+? -4=- 12? =-59 choose D.

7. The rule is that the sum of the first item plus the hundredth, tenth and third digits of the first item is the second item. For example:

256+(2+5+6)=269

269+(2+6+9)=286

......

So the number in brackets is 302+(3+0+2)=307. Choose B.

These topics are quite difficult, but after careful observation and several attempts, you can still find the rules. I wish you success in your exam!